Project Euler 21 - Amicable numbers

Official link: https://projecteuler.net/problem=21

Thought Process

I modified my Divisors Function to make it return the sum of unique divisors, then I simply loop from 1 to 10,000 and if x = Divisors(Divisors(x)) then we have found an amicable number, all we need to do is remove the edge case if x = Divisors(x)

Interactive Code

Input an integer (yourinput)

Code will output the sum of all amicable numbers less than yourinput along with the actual amicable numbers